Q1. A 2 kg ball is dropped from a height of 5 m. Find its kinetic energy just before hitting the ground (g = 10).
At the top: PE = mgh = 2 × 10 × 5 = 100 J
By conservation of energy, all PE → KE
KE just before impact = 100 J
Work, energy and power are three of the most tested ideas in Class 9. Compute each one live, then drill the numericals until the formulas stick.
Try different forces, masses, speeds and heights and watch the energies change (g = 10 m/s²).
Notice kinetic energy depends on the SQUARE of speed — double the speed means four times the energy (and braking distance).
Work, KE, PE and power problems with full solutions (g = 10 m/s²).
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Q1. A 2 kg ball is dropped from a height of 5 m. Find its kinetic energy just before hitting the ground (g = 10).
At the top: PE = mgh = 2 × 10 × 5 = 100 J
By conservation of energy, all PE → KE
KE just before impact = 100 J
Q2. An electric bulb of 60 W is used for 5 hours a day. Find the energy in kWh used in 30 days.
Energy/day = 60 W × 5 h = 300 Wh = 0.3 kWh
In 30 days = 0.3 × 30 = 9 kWh (units)
| Quantity | Formula | SI unit |
|---|---|---|
| Work done | W = F·s | joule (J) |
| Kinetic energy | KE = ½ m v² | J |
| Potential energy | PE = m g h | J |
| Work–energy theorem | W = ΔKE | J |
| Power | P = W / t | watt (W) |
| Commercial unit of energy | 1 kWh = 3.6 × 10⁶ J | kWh |
Work is done only when a force acts on a body and the body moves in the direction of the force: W = F·s.
The net work done on a body equals the change in its kinetic energy: W = ΔKE.
Energy (joule) is the capacity to do work; power (watt) is how fast that work is done, P = W/t.
The kilowatt-hour (kWh), also called a "unit". 1 kWh = 3.6 × 10⁶ J.
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