Q1. Calculate the force between two 5 kg and 10 kg masses kept 0.5 m apart. (G = 6.67×10⁻¹¹)
F = G m₁ m₂ / r²
F = 6.67×10⁻¹¹ × 5 × 10 / (0.5)²
F = 6.67×10⁻¹¹ × 50 / 0.25 = 1.33×10⁻⁸ N
Why does a dropped pen fall but the Moon doesn't? Same law, different speeds. Compute gravitational force and free fall, and practise the numericals examiners love.
Find weight on Earth and the speed/height of a freely falling body (g = 9.8 m/s²).
In free fall every object speeds up at the same rate (9.8 m/s²) — a feather and a stone fall together in a vacuum.
Free-fall and weight problems with worked steps (take g = 10 m/s²).
Loading…
Q1. Calculate the force between two 5 kg and 10 kg masses kept 0.5 m apart. (G = 6.67×10⁻¹¹)
F = G m₁ m₂ / r²
F = 6.67×10⁻¹¹ × 5 × 10 / (0.5)²
F = 6.67×10⁻¹¹ × 50 / 0.25 = 1.33×10⁻⁸ N
Q2. A boy weighs 600 N on Earth. What is his mass, and his weight on the Moon (g_moon = g/6)?
m = W/g = 600/10 = 60 kg (mass is unchanged)
Weight on Moon = 600/6 = 100 N
| Quantity | Formula | SI unit |
|---|---|---|
| Gravitational force | F = G m₁ m₂ / r² | N (G = 6.67×10⁻¹¹) |
| Acceleration due to gravity | g = G M / R² | m/s² |
| Weight | W = m g | N |
| Free fall (from rest) | v = g t, h = ½ g t² | m/s, m |
| Pressure | P = F / A | pascal (Pa) |
| Relative density | R.D. = density of substance / density of water | — (no unit) |
Every object attracts every other object with a force F = G·m₁·m₂/r², proportional to the product of their masses and inversely proportional to the square of the distance between them.
Mass (kg) is the amount of matter in a body and is constant. Weight (newton) is the gravitational force on it, W = m·g, and varies with g.
Because the Moon's gravitational acceleration is about one-sixth of Earth's, so W = m·g is about one-sixth, even though the mass is unchanged.
A body immersed in a fluid experiences an upward buoyant force equal to the weight of the fluid it displaces.
Hi! Found an error or have a suggestion? Let us know and we'll fix it.
Thanks! Your feedback has been sent. We'll look into it.