Q1. A heat engine takes 1000 J from a source and rejects 600 J to the sink. Find its efficiency.
η = 1 − Q₂/Q₁ = 1 − 600/1000
η = 1 − 0.6 = 0.4
η = 40%
Heat and work are two sides of energy. Learn the laws of thermodynamics and compute the efficiency of an ideal heat engine.
Enter the source and sink temperatures (in kelvin) to get the maximum possible efficiency.
Efficiency rises as the temperature difference grows; it can never reach 100% (that would need T_c = 0 K).
Efficiency and first-law problems with steps.
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Q1. A heat engine takes 1000 J from a source and rejects 600 J to the sink. Find its efficiency.
η = 1 − Q₂/Q₁ = 1 − 600/1000
η = 1 − 0.6 = 0.4
η = 40%
Q2. In an adiabatic process, why does a gas cool when it expands?
Adiabatic means no heat is exchanged (Q = 0).
First law: 0 = ΔU + W, so ΔU = −W.
The gas does work by expanding, so its internal energy (and temperature) falls.
| Quantity | Formula | SI unit |
|---|---|---|
| First law | Q = ΔU + W | joule (J) |
| Efficiency | η = W / Q₁ = 1 − Q₂/Q₁ | — |
| Carnot efficiency | η = 1 − T_c / T_h | — |
| Work (isobaric) | W = P ΔV | J |
Heat supplied to a system equals the increase in its internal energy plus the work done by it: Q = ΔU + W (conservation of energy).
η = 1 − T_c/T_h, the maximum efficiency possible between a hot source at T_h and a cold sink at T_c (in kelvin).
A process in which no heat enters or leaves the system (Q = 0), so any work done changes the internal energy.
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