Q1. In a hydraulic lift the small piston has area 0.01 m² and the large one 0.5 m². What force on the small piston lifts a 5000 N load?
Pascal's law: F₁/A₁ = F₂/A₂
F₁ = F₂ × A₁/A₂ = 5000 × 0.01/0.5
F₁ = 100 N
From hydraulic lifts to aeroplane wings, fluids follow a few neat laws. Compute pressure at depth and master buoyancy and Bernoulli.
Find the pressure at a given depth in a fluid of known density (g = 9.8 m/s²).
This is the pressure due to the fluid alone; add atmospheric pressure (≈1.01×10⁵ Pa) for the absolute pressure.
Pressure and buoyancy problems with steps.
Loading…
Q1. In a hydraulic lift the small piston has area 0.01 m² and the large one 0.5 m². What force on the small piston lifts a 5000 N load?
Pascal's law: F₁/A₁ = F₂/A₂
F₁ = F₂ × A₁/A₂ = 5000 × 0.01/0.5
F₁ = 100 N
Q2. Why does an aeroplane wing generate lift?
Air moves faster over the curved top than the flatter bottom.
By Bernoulli's principle, faster flow means lower pressure on top.
The higher pressure below pushes the wing up (lift).
| Quantity | Formula | SI unit |
|---|---|---|
| Pressure at depth | P = ρ g h | pascal (Pa) |
| Pascal's law (hydraulic) | F₁/A₁ = F₂/A₂ | — |
| Buoyant force | F_B = ρ_fluid × V × g | N |
| Bernoulli's equation | P + ½ρv² + ρgh = constant | — |
It increases linearly with depth: P = ρgh, where ρ is the density and h the depth below the surface.
A body immersed in a fluid experiences an upward buoyant force equal to the weight of the fluid displaced.
For a flowing fluid, where the speed is higher the pressure is lower (P + ½ρv² + ρgh is constant).
Hi! Found an error or have a suggestion? Let us know and we'll fix it.
Thanks! Your feedback has been sent. We'll look into it.