Q1. Find the rms speed of oxygen molecules (M = 32 g/mol) at 300 K.
v_rms = √(3RT/M) = √(3 × 8.314 × 300 / 0.032)
v_rms = √(233 831)
v_rms ≈ 484 m/s
A gas is just countless tiny particles in motion. Connect pressure and temperature to molecular speeds and compute the rms speed.
Enter the temperature and molar mass of a gas to find the root-mean-square speed of its molecules.
At room temperature oxygen molecules zip along at nearly 480 m/s — faster than a passenger jet.
RMS-speed and ideal-gas problems with steps.
Loading…
Q1. Find the rms speed of oxygen molecules (M = 32 g/mol) at 300 K.
v_rms = √(3RT/M) = √(3 × 8.314 × 300 / 0.032)
v_rms = √(233 831)
v_rms ≈ 484 m/s
Q2. At what temperature is the average KE of a molecule 6.21×10⁻²¹ J? (k = 1.38×10⁻²³)
KE = (3/2)kT ⇒ T = 2KE/(3k)
T = 2 × 6.21×10⁻²¹ / (3 × 1.38×10⁻²³)
T = 300 K
| Quantity | Formula | SI unit |
|---|---|---|
| Ideal gas equation | P V = n R T | — |
| RMS speed | v_rms = √(3RT/M) | m/s |
| Average KE per molecule | (3/2) k T | J |
| Pressure (kinetic) | P = (1/3) ρ v_rms² | Pa |
PV = nRT, relating pressure, volume, amount (moles) and temperature of an ideal gas, with R = 8.314 J/mol·K.
The root-mean-square speed of gas molecules, v_rms = √(3RT/M); it increases with temperature and decreases with molar mass.
The absolute temperature is directly proportional to the average translational kinetic energy of the molecules.
Hi! Found an error or have a suggestion? Let us know and we'll fix it.
Thanks! Your feedback has been sent. We'll look into it.