Q1. Write the truth table output of a NAND gate for inputs A = 1, B = 1.
A NAND gate gives Y = NOT (A AND B).
A AND B = 1 AND 1 = 1
Y = NOT 1 = 0
The chapter behind every phone and computer. Learn semiconductors, diodes and logic gates, and compute a transistor's current gain.
Enter the collector and base currents to find the common-emitter current gain β.
A small base current controls a much larger collector current — that is how a transistor amplifies.
Transistor current-gain problems with steps.
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Q1. Write the truth table output of a NAND gate for inputs A = 1, B = 1.
A NAND gate gives Y = NOT (A AND B).
A AND B = 1 AND 1 = 1
Y = NOT 1 = 0
Q2. A transistor has I_B = 20 µA and I_C = 4 mA. Find β and I_E.
β = I_C/I_B = 4×10⁻³ / 20×10⁻⁶ = 200
I_E = I_B + I_C = 0.02 + 4 = 4.02 mA
| Quantity | Formula | SI unit |
|---|---|---|
| Current gain (common-emitter) | β = I_C / I_B | — |
| Emitter current | I_E = I_B + I_C | ampere (A) |
| OR gate | Y = A + B | logic |
| AND gate | Y = A · B | logic |
| NOT gate | Y = Ā | logic |
n-type is doped with pentavalent atoms giving extra electrons (majority carriers); p-type is doped with trivalent atoms giving extra holes (majority carriers).
A circuit using diodes to convert alternating current (AC) into direct current (DC); it can be half-wave or full-wave.
Because any other logic gate (AND, OR, NOT, etc.) can be built using only NAND gates or only NOR gates.
In the common-emitter configuration, β = I_C/I_B — the factor by which a small base current is amplified into the collector current.
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