Q1. Find the remainder when x³ − 3x² + 4 is divided by (x − 2).
By the remainder theorem, remainder = p(2)
p(2) = 2³ − 3(2²) + 4 = 8 − 12 + 4 = 0
So the remainder is 0 (and x − 2 is a factor).
Polynomials factor beautifully once you know the identities and the factor theorem. Master both for the exam.
Q1. Find the remainder when x³ − 3x² + 4 is divided by (x − 2).
By the remainder theorem, remainder = p(2)
p(2) = 2³ − 3(2²) + 4 = 8 − 12 + 4 = 0
So the remainder is 0 (and x − 2 is a factor).
Q2. Factorise x² + 5x + 6.
Find two numbers with product 6 and sum 5: 2 and 3
x² + 5x + 6 = (x + 2)(x + 3)
| Quantity | Formula |
|---|---|
| Square of a sum | (a+b)² = a² + 2ab + b² |
| Difference of squares | a² − b² = (a+b)(a−b) |
| Sum of cubes | a³ + b³ = (a+b)(a²−ab+b²) |
| (a+b+c)² | a²+b²+c²+2(ab+bc+ca) |
When a polynomial p(x) is divided by (x − a), the remainder equals p(a).
(x − a) is a factor of p(x) if and only if p(a) = 0.
The highest power of the variable in the polynomial.
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