Q1. A die is thrown. Given the number is even, find the probability it is 2.
B = even = {2, 4, 6}, so P(B) = 3/6
A∩B = {2}, so P(A∩B) = 1/6
P(A|B) = (1/6)/(3/6) = 1/3
Class 12 probability is all about conditions. Master conditional probability and Bayes' theorem, and compute basic probabilities live.
Enter P(A∩B) and P(B) to get the conditional probability P(A|B).
For independent events P(A|B) = P(A), so the condition makes no difference.
Q1. A die is thrown. Given the number is even, find the probability it is 2.
B = even = {2, 4, 6}, so P(B) = 3/6
A∩B = {2}, so P(A∩B) = 1/6
P(A|B) = (1/6)/(3/6) = 1/3
| Quantity | Formula |
|---|---|
| Conditional probability | P(A|B) = P(A∩B)/P(B) |
| Multiplication | P(A∩B) = P(A)·P(B|A) |
| Independent events | P(A∩B) = P(A)·P(B) |
P(A|B) = P(A∩B)/P(B), the probability of A given that B has already occurred.
P(A∩B) = P(A)·P(B|A); for independent events it becomes P(A)·P(B).
To find the probability of a cause given an observed effect, by reversing a conditional probability.
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