Q1. How many 3-letter words (no repeats) can be formed from A, B, C, D?
Order matters ⇒ permutation ⁴P₃
⁴P₃ = 4!/(4−3)! = 24/1
= 24 words
Order matters for permutations, not for combinations. Compute both instantly and learn when to use which.
Enter n and r to get the number of permutations (arrangements) and combinations (selections).
Counting problems with steps.
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Q1. How many 3-letter words (no repeats) can be formed from A, B, C, D?
Order matters ⇒ permutation ⁴P₃
⁴P₃ = 4!/(4−3)! = 24/1
= 24 words
| Quantity | Formula |
|---|---|
| Permutations | ⁿPᵣ = n! / (n − r)! |
| Combinations | ⁿCᵣ = n! / [r!(n − r)!] |
| Relation | ⁿPᵣ = r! · ⁿCᵣ |
| Symmetry | ⁿCᵣ = ⁿCₙ₋ᵣ |
A permutation counts arrangements (order matters); a combination counts selections (order does not matter).
ⁿCᵣ = n! / [r!(n − r)!].
0! is defined to be 1.
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