Q1. The sides of two similar triangles are in the ratio 2:3. If the area of the smaller is 20 cm², find the area of the larger.
Ratio of areas = (ratio of sides)² = (2/3)² = 4/9
Area of larger = 20 × (9/4)
Area of larger = 45 cm²
Similar triangles have the same shape at different sizes. Master the criteria, then use the calculator to find any side of a right triangle instantly.
Enter the two legs of a right triangle to find the hypotenuse — or a leg and the hypotenuse to find the other leg.
To find a leg instead, use c² − a² = b², i.e. rearrange: b = √(c² − a²).
Pythagoras and similar-triangle problems with steps.
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Q1. The sides of two similar triangles are in the ratio 2:3. If the area of the smaller is 20 cm², find the area of the larger.
Ratio of areas = (ratio of sides)² = (2/3)² = 4/9
Area of larger = 20 × (9/4)
Area of larger = 45 cm²
| Quantity | Formula |
|---|---|
| Pythagoras theorem | c² = a² + b² |
| Ratio of areas of similar triangles | = (ratio of sides)² |
| Basic proportionality theorem | AD/DB = AE/EC |
In a right-angled triangle, the square of the hypotenuse equals the sum of the squares of the other two sides: c² = a² + b².
If a line is drawn parallel to one side of a triangle intersecting the other two sides, it divides those sides in the same ratio (also called Thales' theorem).
The ratio of the areas equals the square of the ratio of the corresponding sides.
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