Class 10 · CBSE / NCERT · Mathematics

Coordinate Geometry — Class 10

Turn geometry into arithmetic. Compute the distance and midpoint between any two points, then master the section and area formulas.

Distance formulaBetween (x₁,y₁) and (x₂,y₂): d = √[(x₂−x₁)² + (y₂−y₁)²].
Section formulaThe point dividing the join of two points in ratio m:n is ((mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)).
MidpointThe midpoint of (x₁,y₁) and (x₂,y₂) is ((x₁+x₂)/2, (y₁+y₂)/2).

Distance & midpoint calculator Interactive

Enter two points to get the distance between them and their midpoint.

Distance
Midpoint x
Midpoint y

The distance of a point (x, y) from the origin is simply √(x² + y²).

Numericals practice Interactive

Distance-formula problems with steps.

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Solved examples

Q1. Find the distance between (1, 2) and (4, 6).

d = √[(4−1)² + (6−2)²]

d = √[9 + 16] = √25

d = 5 units

Formula sheet

QuantityFormula
Distanced = √[(x₂−x₁)² + (y₂−y₁)²]
Midpoint((x₁+x₂)/2, (y₁+y₂)/2)
Area of triangle½ |x₁(y₂−y₃) + x₂(y₃−y₁) + x₃(y₁−y₂)|

Common mistakes & exam wins

  • The distance formula is just Pythagoras' theorem in disguise.
  • For the midpoint, take the average of the x-coordinates and the average of the y-coordinates.
  • Three points are collinear if the area of the triangle they form is 0.

Frequently asked questions

What is the distance formula?

The distance between (x₁,y₁) and (x₂,y₂) is √[(x₂−x₁)² + (y₂−y₁)²].

What is the section formula?

The point dividing the segment joining two points in ratio m:n is ((mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)).

How do you check if three points are collinear?

They are collinear if the area of the triangle formed by them is zero.