Q1. Which term of the AP 3, 8, 13, … is 78?
a = 3, d = 5, aₙ = 78
78 = 3 + (n − 1)×5 ⇒ 75 = 5(n − 1) ⇒ n − 1 = 15
n = 16, so 78 is the 16th term.
An AP just adds the same number each time. Compute any term and the sum instantly, then practise the board numericals.
Enter the first term, common difference and n to get the nth term and the sum.
To check if a number belongs to an AP, solve a + (n−1)d = that number for n — it must be a positive whole number.
nth-term and sum problems with steps.
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Q1. Which term of the AP 3, 8, 13, … is 78?
a = 3, d = 5, aₙ = 78
78 = 3 + (n − 1)×5 ⇒ 75 = 5(n − 1) ⇒ n − 1 = 15
n = 16, so 78 is the 16th term.
| Quantity | Formula |
|---|---|
| nth term | aₙ = a + (n − 1)d |
| Sum of n terms | Sₙ = n/2 [2a + (n − 1)d] |
| Sum (with last term l) | Sₙ = n/2 (a + l) |
aₙ = a + (n − 1)d, where a is the first term and d the common difference.
Sₙ = n/2 [2a + (n − 1)d], or Sₙ = n/2 (a + l) if the last term l is known.
Subtract any term from the next one: d = aₙ₊₁ − aₙ.
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