Q1. Find the area of a sector with radius 7 cm and angle 90° (π = 22/7).
Area = (θ/360°) × πr²
Area = (90/360) × (22/7) × 7²
Area = ¼ × 22/7 × 49 = ¼ × 154 = 38.5 cm²
A pizza slice is a sector; the crust-only bit beyond a chord is a segment. Compute both areas — and the arc length — instantly.
Enter the radius and the angle at the centre to get the arc length and the sector area (π ≈ 3.1416).
A sector with θ = 360° is the whole circle; a sector with θ = 180° is a semicircle.
Sector area problems with steps (π = 22/7).
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Q1. Find the area of a sector with radius 7 cm and angle 90° (π = 22/7).
Area = (θ/360°) × πr²
Area = (90/360) × (22/7) × 7²
Area = ¼ × 22/7 × 49 = ¼ × 154 = 38.5 cm²
| Quantity | Formula |
|---|---|
| Circumference | C = 2πr |
| Area of circle | A = πr² |
| Arc length | l = (θ/360°) × 2πr |
| Area of sector | A = (θ/360°) × πr² |
| Area of segment | sector area − triangle area |
A sector is bounded by two radii and an arc (a "pie slice"); a segment is bounded by a chord and an arc.
Area = (θ/360°) × πr², where θ is the angle at the centre and r the radius.
Subtract the area of the triangle (formed by the two radii and the chord) from the area of the sector.
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